Vector addition and subtraction: component and parallelogram methods

by Quirino Sugon Jr.

The sum and difference of vectors a and b

The sum and difference of vectors a = (3,4) and b = (6,0)

Suppose we choose two points on the Cartesian coordinate system: (3,4) and (6,0).  If we interpret these points as tips of the rays–which we shall now call as vectors–drawn from the origin at $(0,0)$, then we write down our vectors as

(1a)\qquad \vec a = (3,4),

(1b)\qquad\, \vec b = (6,0).

The sum and difference of these two vectors is given by

(2a) \qquad \vec c = \vec a+\vec b = (3+6, 4+0)=(9,4).

(2b) \qquad \vec d = \vec a-\vec b = (3-6, 4-0)=(-3,4).

The parenthesis-and-comma notation for vectors is not amenable to algebraic manipulation. To solve this problem, we introduce two unit vectors (vectors of unit length) \hat\imath and \hat\jmath. The unit vector \hat\imath points in the direction of positive x-axis, while \hat\jmath points in the direction of positive y-axis. Using these two unit vectors, let us rewrite Eqs. (1a) and (1b) as

(3a)\qquad \vec a= 3\hat\imath + 4\hat\jmath,

(3a)\qquad \vec b= 6\hat\imath + 0\hat\jmath = 6\hat\imath,

Hence,

(4a) \qquad \vec c = \vec a+\vec b = 3\hat\imath+4\hat\jmath+6\hat\imath = 9\hat\imath + 6\hat\jmath,

(4b) \qquad \vec d = \vec a-\vec b = 3\hat\imath+4\hat\jmath-6\hat\imath = 3\hat\imath - 6\hat\jmath.

It feels natural, doesn’t it?  You add only like terms: those with \hat\imath are added to those with \hat\imath; those with \hat\jmath are added to those with \hat\jmath.  If you have a bag containing 3 apples and 4 oranges and another bag containing 6 apples, then putting all these in a single bag results to 9 apples and 4 oranges.  This is an interpretation of \vec a + \vec b.  What do you think is the corresponding interpretation for \vec a - \vec b?

The sum and difference of vectors a and b using parallelogram method

The sum and difference of vectors a and b using parallelogram method

The apples-and-oranges interpretation, though helpful, is not really precise.  The proper interpretation is geometrical.  In order to interpret \vec a+\vec b and \vec a-\vec b geometrically, we need to draw them together with \vec a and \vec b (see Fig. 1).  Notice that if we construct a parallelogram with \vec a as two of the parallel sides and \vec b as the other two parallel sides, then \vec a+\vec b corresponds to one diagonal and \vec a - \vec b corresponds to the other diagonal.

Let us write down some rules.  To draw \vec a+\vec b, connect the tail of \vec b to the tip of \vec a, then draw \vec a+\vec b as the vector  from the tail of vector \vec a to the tip of \vec b.  On the other hand, to draw \vec a-\vec b, connect the tails of vectors \vec a and \vec b, then draw \vec a - \vec b as the vector from the tip of \vec b to the tip of \vec a.

In general, we can let the coefficients of \vec a and \vec b to be any scalar, and we can even include a new unit vector \hat k along the positive z-axis.  If we do this, then

(5a) \qquad \vec a = a_1\hat\imath + a_2\hat\jmath + a_3\hat k,

(5b) \qquad \vec b = b_1\hat\imath + b_2\hat\jmath + b_3\hat k,

so that

(6a) \qquad \vec a + \vec b= (a_1+b_1)\hat\imath + (a_2+b_2)\hat\jmath + (a_3+b_3)\hat k,

(6b) \qquad \vec a - \vec b= (a_1-b_1)\hat\imath + (a_2-b_2)\hat\jmath + (a_3-b_3)\hat k.

Equations (6a) and (6b) are the algebraic rules for vector addition and subtraction in three dimensions.  The geometrical interpretation is still the same as that for two dimensions.

About ateneophysicsnews
Physics News and Features from Ateneo de Manila University

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